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Use Leibniz's rule to find dy/dx.

**Leibniz's rule: If g(x) and h(x) are differentiable functions and f(u) is continuous for u between g(x) and h(x), then
d/dx of the integral from g(x) to h(x) of f(u) du = f[h(x)]h'(x) - f[g(x)]g'(x)

y = the integral from 2+x² to 2 of (cot t) dt

  • Calculus -

    What's to worry about? You have the formula, just plug in f,g,h. The only possible sticking spot is knowing that Int(cot(t) dt] = ln sin t

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