Nitrogen effused through a pinhole 1.7times as fast as another gaseous element at the same conditions.Estimate the other element's molar mass. Answer in units of g/mol
81.
To estimate the other element's molar mass based on the given information, we can use Graham's Law of Effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Let's call the molar mass of the other element "M". According to Graham's Law, the ratio of the effusion rates of nitrogen (N2) to the other element can be expressed as:
(rate of nitrogen)/(rate of other element) = √(Molar mass of other element)/(Molar mass of nitrogen)
Using the information given, we can set up the equation as follows:
1.7 = √(Molar mass of other element)/(Molar mass of nitrogen)
Squaring both sides of the equation to eliminate the square root:
(1.7)^2 = (Molar mass of other element)/(Molar mass of nitrogen)
2.89 ≈ (Molar mass of other element)/(Molar mass of nitrogen)
Next, let's find the molar mass of nitrogen (N2). The molar mass of nitrogen (N2) is approximately 28 g/mol.
Now, we can plug in the values into the equation:
2.89 ≈ (Molar mass of other element)/(28 g/mol)
Rearranging the equation to solve for the molar mass of the other element:
Molar mass of other element ≈ 2.89 * 28 g/mol
Calculating the approximate molar mass of the other element:
Molar mass of other element ≈ 80.92 g/mol
Therefore, the estimated molar mass of the other element is approximately 80.92 g/mol.