34.42mL of 0.1013 M NaOH is used to titrate a 25.00 mL sample of H2SO
6.97x10^-2 M
To determine the concentration of H2SO4 in the solution, we can use the equation:
NaOH + H2SO4 -> Na2SO4 + H2O
Given:
Volume of NaOH solution (V1) = 34.42 mL
Molarity of NaOH solution (M1) = 0.1013 M
Volume of H2SO4 sample (V2) = 25.00 mL
Step 1: Convert the volume of NaOH solution from mL to L
V1 = 34.42 mL = 34.42/1000 L = 0.03442 L
Step 2: Calculate the number of moles of NaOH (n1) using the equation:
n1 = M1 * V1
n1 = 0.1013 M * 0.03442 L
Step 3: According to the balanced equation, the stoichiometric ratio between NaOH and H2SO4 is 1:1.
So, the number of moles of NaOH (n1) is equal to the number of moles of H2SO4 (n2).
Step 4: Convert the volume of H2SO4 sample from mL to L.
V2 = 25.00 mL = 25.00/1000 L = 0.02500 L
Step 5: Calculate the concentration of H2SO4 (M2) using the equation:
M2 = n2/V2
M2 = n1/0.02500 L
Step 6: Substitute the value of n1 into the equation:
M2 = (0.1013 M * 0.03442 L) / 0.02500 L
M2 = 0.1386912 M
Therefore, the concentration of H2SO4 in the solution is approximately 0.1387 M.
To find the concentration of the sulfuric acid (H2SO4) solution, we can use the information provided about the titration with sodium hydroxide (NaOH). The balanced chemical equation for the reaction between NaOH and H2SO4 is:
2 NaOH + H2SO4 -> Na2SO4 + 2 H2O
From the balanced equation, we can see that the ratio of NaOH to H2SO4 is 2:1. This means that 2 moles of NaOH react with 1 mole of H2SO4.
Given that 34.42 mL of 0.1013 M NaOH is required to completely neutralize the 25.00 mL sample of H2SO4, we can determine the number of moles of NaOH used.
First, calculate the number of moles (n) of NaOH using the molarity (M) and volume (V) of the NaOH solution:
n(NaOH) = M(NaOH) * V(NaOH)
n(NaOH) = 0.1013 mol/L * 0.03442 L
n(NaOH) = 0.003483 mol
Since the ratio of NaOH to H2SO4 is 2:1, we know that the number of moles of H2SO4 is also 0.003483 mol.
Next, we need to determine the concentration (M) of the H2SO4 solution.
M(H2SO4) = n(H2SO4) / V(H2SO4)
M(H2SO4) = 0.003483 mol / 0.02500 L
M(H2SO4) = 0.1393 M
Therefore, the concentration of the sulfuric acid (H2SO4) solution is 0.1393 M.