the base of a triangle is 3cm greater thanthe height.the area is 27cm find the heightand base of the triangle

height -- x

base -- x+3

(1/2)x(x+3) = 27
x^2 + 3x = 54
x^2 + 3x - 54 = 0
(x+9)(x-6) = 0
x = -9 (no good) or x = 6

height = 6
base = 9

To find the height and base of the triangle, let's use the formula for the area of a triangle:

Area = (1/2) * base * height

We know that the area is 27 cm², so we can substitute this value into the formula:

27 = (1/2) * base * height

Since the base is 3 cm greater than the height, we can express the base as (height + 3). Substituting this into the equation, we get:

27 = (1/2) * (height + 3) * height

To solve for the height, we can rearrange the equation:

54 = (height + 3) * height

Expanding the equation:

54 = height^2 + 3height

Rearranging to form a quadratic equation:

height^2 + 3height - 54 = 0

Now, we can solve this equation for the height using factoring, completing the square, or quadratic formula:

(height + 9)(height - 6) = 0

Setting each factor to zero:

height + 9 = 0 OR height - 6 = 0

Solving for height:

height = -9 OR height = 6

We can disregard the negative value since height cannot be negative in this context. Therefore, the height of the triangle is 6 cm.

To find the base, we can substitute the height value into the equation for the base:

base = height + 3 = 6 + 3 = 9 cm

Thus, the height of the triangle is 6 cm and the base is 9 cm.

To find the height and base of the triangle, we can use the formula for the area of a triangle:

Area = (1/2) * base * height

Given that the area is 27 cm², we can substitute the values into the formula and solve for the unknown variables. Let's name the height as 'h' and the base as 'b'.

27 = (1/2) * b * h

Now, we are also given that the base is 3 cm greater than the height. We can express this as:

b = h + 3

Substituting this value for 'b' in the area formula:

27 = (1/2) * (h + 3) * h

Now, let's simplify the equation and solve for 'h':

54 = (h + 3) * h

Expanding the equation:

54 = h² + 3h

Rearranging the equation to make it quadratic:

h² + 3h - 54 = 0

Now we can solve this quadratic equation by factoring or using the quadratic formula:

(h + 9)(h - 6) = 0

From this equation, we find two possible values for 'h': h = -9 or h = 6. Since the height cannot be negative, we discard h = -9 and consider h = 6.

Now, substitute the value of 'h' back into the equation for 'b':

b = h + 3
b = 6 + 3
b = 9

So, the height of the triangle is 6 cm and the base is 9 cm.