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A stone is thrown from ground level at 70m/s. Its speed when it reaches its highest point is 48 m/s. Find the angle, above the horizontal, of the stone’s initial velocity.

  • physics -

    Check me on this, I'm a little rusty.

    The initial velocity is 70. Since the horizontal speed never changed, that means that the x-component was 48. So, cos θ = 48/70, so θ = 46.7°

  • physics -

    thank you

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