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how many moles of H2SO4 are required to react with 2.63 mol of AL
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what is the theoritical yield when 2.7 moles of X react with 1.3 moles of Y
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According to the reaction 2Al+3H2SO4→3H2+Al2(SO4)3, the total number of moles of H2SO4 needed to react completely with 5.0 mol
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7.5
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. How many grams of H2SO4 (98.1 g·mol-1) are required to react with 4.0 g NaOH (40.0 g·mol-1) in this neutralization
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Here is a worked example. http://www.jiskha.com/science/chemistry/stoichiometry.html
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25cm^3 of a solution of NaOH required 28cm^3 of 1.0 mol dm^-3 H2SO4 to neutralise it. a)Write an
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In a reaction vessel, 2.4 mol of Al(OH)3 and 5.3 mol of H2SO4 react.
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You are correct that Al(OH)3 is the limiting reagent. I don't know how you calculated that but that
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How many moles of carbon are needed to react with 5.01 mol SO2?
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You need an equation.
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Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O.
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How many moles of sulfuric acid are required to neutralize 0.80 mol of sodium hydroxide?
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How many moles of Al(OH) are required to completely react with 2.75mol of H2SO4?
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In what reaction? This one? Al(OH)3+ 3H2SO4 >>Al2(SO4)3 + 3H2O you need 1/3 the moles, or 2.75/3
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What mass of H2SO4 would be required to react with 0.59 mol of NaOH?
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