Kevin has a rabbit, a ferret, a gerbil and a turtle. He feeds them in a different order each day. In how many different orders can Kevin feed his pets?
6 ways
He has four animals.\
the first day he has four choices
the second day he has three choices
the third day he has two choices
the last day..
numberways: 4*3*2*!=24 ways
To find the number of different orders Kevin can feed his pets, we need to use the concept of permutations. A permutation is an arrangement of objects where the order matters. In this case, the order in which Kevin feeds his pets matters because each day he feeds them in a different order.
Since Kevin has 4 pets, the number of different orders can be calculated using the formula for permutations:
nPr = n! / (n - r)!
Where n is the total number of objects (pets) and r is the number of objects chosen (in this case, all of them).
In this case, we have 4 pets and want to find the number of different orders in which Kevin can feed them:
4P4 = 4! / (4 - 4)!
= 4! / 0!
= 4! / 1
= 4 x 3 x 2 x 1
= 24
Therefore, Kevin can feed his pets in 24 different orders.