Ms. Sue thanks a ton for solveing my last problem. But now I have another one. Can you help??? "Tanya's age is ten years greater than half Aarons age. If the sum of their ages is 55, how old is Tanya? also do you think you could explain how to do this so I can do it to?
T-10=1/2 A
T+A=55
Can you do it from here?
no that's where i've been getting stuck :(
I don't know why i don't understand this stuff. its just so frustrating!
can anyone at least explain the question??
Of course, I'd be happy to help you solve this problem and explain the process to you!
Let's start by defining the variables:
Let T represent Tanya's age.
Let A represent Aaron's age.
We are given two pieces of information:
1. Tanya's age is ten years greater than half Aaron's age: T = (1/2)A + 10.
2. The sum of their ages is 55: T + A = 55.
To solve this system of equations, we can use substitution or elimination method.
Let's use substitution:
Substitute the value of T from equation 1 into equation 2:
((1/2)A + 10) + A = 55.
Now, we can simplify this equation to find the value of A:
(1/2)A + 10 + A = 55.
Multiply every term by 2 to remove the fractions:
A + 20 + 2A = 110,
3A + 20 = 110.
Subtract 20 from both sides:
3A = 90.
Divide both sides by 3:
A = 30.
Now that we have found Aaron's age (A = 30), we can substitute it back into equation 1 to find Tanya's age (T):
T = (1/2)(30) + 10,
T = 15 + 10,
T = 25.
Therefore, Tanya is 25 years old.