Calculate the molarity (M) of Na+ in a solution prepared by adding 1.00 L of 0.800 M NaHC2O4 and 250 mL of 0.300 M NaHC2O4 . Assume volumes are additive.
the answer is 0.700 but im not sure how to go about solving it please help thanks
moles Na from #1 = M x L = ?
moles Na from #2 = M x L = ?
Then M Na in the final solution is total moles/total L.