posted by HM .
There is a question >
Write the slope intercept form of the equation for the line passing through the points (-6,3) and (0,7)
Now my answer started with >
Slope = 7-3/0-(-6) = Slope = 2/3
Then to find the intercept >
3= 2/3(-6) + c
In my opinion this is the only way I could think of besides the formula y0-y1=m(x0-x1) and I tried that and I am getting nothing..
So where am I going wrong?
The right answer according to mathlab is > y=3/4x+8
Unless you have a typo in your original information, the correct equation in y-intercept slope form is
y = (2/3)x + 7 , which is what you had
As was shown by Jesse, the answer they supplied does not verify , so it is wrong.
Both of the given points satisfy your equation.
As a matter of fact (0,7) is the actual y-intercept , thus the b of the equation.
Aha, then is must be a technical error in Mathlab. :/