The faces of a cube are numbered 1-6. If the cube is tossed once, what is the probabilty that a prime number or a number divisible by 2 is obtained.
prime number or even number less than or equal to 6
---> the only number not satisfied by this is the number 1
so prob of above = 5/6
To solve this problem, we need to find the number of favorable outcomes and the total number of possible outcomes.
In this case, the favorable outcomes are numbers that are either prime or divisible by 2. The prime numbers on a cube are 2, 3, and 5, and the numbers divisible by 2 are 2, 4, and 6.
So, the favorable outcomes are: 2, 3, 4, 5, and 6, which is a total of 5 outcomes.
The total number of possible outcomes is 6, since there are 6 different faces on the cube.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 5 / 6
Hence, the probability of obtaining a prime number or a number divisible by 2 when tossing a cube once is 5/6.