To determine the force acting on each mass its was assumed that g=9.80 m/sec2. The value of g at the place where the experiment is performed may be slightly different from value . State what effect it would have on the percentage error calculated for the comparisons. To test your answer to the question, leave g as a symbol in the calculation of percentage error.

How do i answer this question?

Quit school I guess.

To answer this question, you can follow these steps:

Step 1: Identify the given information and what is being asked.
In this case, the given information is that the force acting on each mass was assumed to have a value of g = 9.80 m/sec^2. The question asks about the effect this assumption would have on the percentage error calculated for the comparisons.

Step 2: Understand the concept of percentage error.
Percentage error is a measure of the difference between an assumed or experimental value and the actual value, expressed as a percentage of the actual value. It is calculated using the formula:
Percentage error = [(assumed value - actual value) / actual value] * 100%

Step 3: Consider the effect of a different value of g on the percentage error.
If the value of g at the place where the experiment is performed is slightly different from the assumed value of 9.80 m/sec^2, it would affect the percentage error calculated for the comparisons. The reason is that the assumed value of g is used in the calculations, but the actual value of g may be different.

Step 4: Determine how to incorporate the effect of the different value of g into the calculation of the percentage error.
To test the effect of a different value of g on the percentage error calculated for the comparisons, you can leave g as a symbol in the calculation. This means that instead of using a specific numerical value for g, you would use the symbol g in the formula for percentage error. This allows the calculation to be flexible and account for any value of g that might be present.

For example, if the formula for percentage error is:
Percentage error = [(assumed value - actual value) / actual value] * 100%

You can leave g as a symbol, like this:
Percentage error = [(assumed value - actual value) / actual value] * 100% where g represents the actual value of gravity at the place of the experiment.

By leaving g as a symbol, the calculation of percentage error can be used for any value of g without needing to modify the formula each time.

Step 5: Present your answer.
You can answer the question by stating that leaving the value of g as a symbol in the calculation of percentage error allows the calculation to be flexible and account for any value of g that might be present at the place of the experiment. This approach ensures that the percentage error can be accurately calculated regardless of slight variations in the value of g.

To answer this question, you need to consider the calculation of percentage error and determine the effect of a change in the value of gravitational acceleration (g) on this calculation.

The formula for percentage error is given by:
Percentage Error = |(Measured Value - Actual Value) / Actual Value| * 100

In this case, the actual value is assumed to be g=9.80 m/sec^2. However, the question asks you to leave g as a symbol in the calculation. This means that you should not substitute the assumed value of g into the formula.

Now, suppose there is a slight difference in the value of g at the place where the experiment is being performed. Let's say the actual value of g at this place is slightly different, and we can represent it as g'.

Considering this scenario, we can calculate the percentage error for the force acting on each mass as follows:
Percentage Error = |(Measured Value - Actual Value) / Actual Value| * 100
= |(Measured Value - g') / g'| * 100

Here, the change in the value of g from the assumed value of 9.80 m/sec^2 to g' will affect the calculation of percentage error.

If the actual value of g is less than 9.80 m/sec^2 (g' < 9.80), the measured force will be greater than the expected force, resulting in a positive percentage error.

On the other hand, if the actual value of g is greater than 9.80 m/sec^2 (g' > 9.80), the measured force will be smaller than the expected force, leading to a negative percentage error.

Therefore, the effect of a change in the value of g on the percentage error calculated for the comparisons is that it will alter the sign (positive or negative) of the percentage error. The magnitude of the percentage error will be determined by the difference between the measured value and the actual value of g.

To summarize, if you leave g as a symbol in the calculation of the percentage error, any change in the actual value of g from the assumed value will affect the sign and magnitude of the percentage error calculated for the comparisons.

sjkjck