Chemistry
posted by Maci .
If the pressure on a balloon were quadrupled what would happen to the balloons volume?

P1V1 = P2V2
Since no initial P is given, just make up a value, then quadruple it for P2. 
So just any random number I can quadruple it to?

right. Why not go the easy route and make P1 = 1 and P2 = 4.
Then you need to make V1 = 4 and solve for V2.
Another way to do it is use
P1V1 = P2V2 and set P2 = 4P1
So P1V1 = 4P1V2 and solve for
V1/V2 = 4P1/P1
So V1/V2 = 1P1/4P1, the P1 cancels to obtain
V1/V2 = 4
V1 = 4V2 or
V2 = (V1/4) = 1/4 V1