Chemistry

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If the pressure on a balloon were quadrupled what would happen to the balloons volume?

  • Chemistry -

    P1V1 = P2V2
    Since no initial P is given, just make up a value, then quadruple it for P2.

  • Chemistry -

    So just any random number I can quadruple it to?

  • Chemistry -

    right. Why not go the easy route and make P1 = 1 and P2 = 4.
    Then you need to make V1 = 4 and solve for V2.
    Another way to do it is use
    P1V1 = P2V2 and set P2 = 4P1
    So P1V1 = 4P1V2 and solve for
    V1/V2 = 4P1/P1
    So V1/V2 = 1P1/4P1, the P1 cancels to obtain
    V1/V2 = 4
    V1 = 4V2 or
    V2 = (V1/4) = 1/4 V1

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