A 15.75-g piece of unknown metal absorbs 60 cal of heat energy, and its temperature changes form 25 degrees C to 175 degrees C. Calculate the specific heat capacity of this metal.
To calculate the specific heat capacity of the metal, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy absorbed (in calories)
m is the mass of the metal (in grams)
c is the specific heat capacity of the metal (in calories/gram°C)
ΔT is the change in temperature (in °C)
Given:
Q = 60 cal
m = 15.75 g
ΔT = 175°C - 25°C = 150°C
Plugging in the values, we can rearrange the formula to solve for c:
c = Q / (m * ΔT)
c = 60 cal / (15.75 g * 150°C)
To calculate the specific heat capacity of the metal, we can use the formula:
Q = mcΔT
where:
Q = heat energy absorbed (in calories)
m = mass of the metal (in grams)
c = specific heat capacity of the metal (in cal/g°C)
ΔT = change in temperature (in °C)
In this case, the heat energy absorbed (Q) is given as 60 cal. The mass of the metal (m) is given as 15.75 g. The change in temperature (ΔT) is the final temperature (175°C) minus the initial temperature (25°C), which is 150°C.
Now, we can rearrange the formula to solve for c:
c = Q / (mΔT)
Substituting the given values:
c = 60 cal / (15.75 g * 150°C)
To calculate this, divide 60 cal by the product of 15.75 g and 150°C:
c = 60 cal / (15.75 g * 150°C) = 0.0267 cal/g°C
Therefore, the specific heat capacity of the metal is approximately 0.0267 cal/g°C.