# calculus

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given the graph of f(x) = x sinx, 0<=x<=2pi
assuming that a quantity y changes at a rate of y' = xsinx, find by how much it will increase or decrease over 3pi/2 <= x <= 2pi
the area under the graph from 0 to pi/2 is 1
the area under the graph from pi/2 to pi is pi-1
the area under the graph from pi to 3pi/2 is pi+1
and the area under the graph from 3pi/2 to 2pi is 2pi-1

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