Mrs. Sue Algebra outlier/mean recheck

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find the outlier of each set of data describe how the outlier affects the mean. just want to double check on 2 problems that we did

-15
-12
-19
0
-20
-14
the outlier is 0
the mean with the outlier 0
is: -13.33

the mean without the outlier 0
is: -16
is this correct?

next one:

4
-1
-16
2
0
-3
6
-2
for this i added positive got: 12
i added negative and got: -22
do i do 12 - 22
and get 10
10/8 = 1 2/10 = 1 1/5?? not sure on this one

• Mrs. Sue Algebra outlier/mean recheck -

What is the outlier for the second one?

• Mrs. Sue Algebra outlier/mean recheck -

the outlier is -16 for question 2

• Mrs. Sue Algebra outlier/mean recheck -

Yes.

-10/8 = -1.2

Eliminating -16, the median is ?

• Mrs. Sue Algebra outlier/mean recheck -

eliminating -16 would be
12 -6 = 6 for the mean

• Ms. Sue Algebra outlier/mean recheck -

Nope.

• Mrs. Sue Algebra outlier/mean recheck -

eliminating the -16 would be -6
-1
-3
-2
= -6

so 12 - 6 = 6 as mean w/o -16 outlier

• Mrs. Sue Algebra outlier/mean recheck -

6/7

• Mrs. Sue Algebra outlier/mean recheck -

,857 is the mean
i messed up
12 + -6 = 6
6 /7
= .857
i forgot a step thanks again and again
.857 is the mean without outlier -16

• Mrs. Sue Algebra outlier/mean recheck -

You're welcome.

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