�ã27 + �ã12 - �ã32 - �ã8
�ã27 = �ã3*3*3 = 3�ã3
�ã12 = �ã2*2*3 = 2�ã3
�ã32 = �ã2*2*2*2*2 = 4�ã2
�ã8 = �ã2*2*2 = 2�ã2
3�ã3 + 2�ã3 - 4�ã2 - 2�ã2
Here is where I get sort of confused. Because the like terms are 3. And so Im supposed to add them and I get 5�ã3. Then I subtract the 4�ã2 - 2�ã2 and I get a 2�ã2, but its supposed to be 6.(would that be known as the index? And can indexes be negative??
Ok sorry I just cant make that radical sign for some reason but that ã is supposed to be a radical sign.
U+221A
(0xFB)
To simplify the expression �ã27 + �ã12 - �ã32 - �ã8, we need to combine like terms.
First, let's simplify �ã27 to get 3�ã3.
Similarly, �ã12 simplifies to 2�ã3.
�ã32 simplifies to 4�ã2.
And �ã8 simplifies to 2�ã2.
Now we can rewrite the expression as:
3�ã3 + 2�ã3 - 4�ã2 - 2�ã2.
To combine like terms, you need to add or subtract the coefficients (the numbers in front of the radical) only if the indexes (the number inside the radical) and the radicands (the number under the radical) are the same.
In this case, you have 3�ã3 and 2�ã3. Since the indexes are the same (both are 3) and the radicands are the same (both are 3), you can add the coefficients. Thus, 3�ã3 + 2�ã3 gives you 5�ã3.
Next, you have -4�ã2 and -2�ã2. Again, the indexes and radicands are the same (both are 2), so you can subtract the coefficients. -4�ã2 - 2�ã2 gives you -6�ã2 (not 6�ã2).
Therefore, the simplified expression is 5�ã3 - 6�ã2.