How many silver coins (weighing 26g each) would it take to provide 5 moles of silver(Ag).
1 mole Ag = 107.87 so 5 moles is 5*that = approximately 540 g. So how many coins at 26g each will make 540 grams?
To determine the number of silver coins needed to provide 5 moles of silver (Ag), we need to use the molar mass of silver. The molar mass of silver is 107.87 g/mol.
First, we need to convert the given weight of each silver coin into moles. To do this, divide the weight of each coin by the molar mass of silver:
Weight of each coin = 26 g
Molar mass of silver (Ag) = 107.87 g/mol
Number of moles in each coin = Weight of each coin / Molar mass of silver
= 26 g / 107.87 g/mol
≈ 0.241 mol
Next, we can calculate the number of coins needed to obtain 5 moles of silver by dividing the desired moles of silver by the moles in each coin:
Number of coins = Desired moles of silver / Moles in each coin
= 5 mol / 0.241 mol/coin
≈ 20.75 coins
Since you can't have a fraction of a coin, you would need to round up to the nearest whole number. Therefore, you would need approximately 21 silver coins weighing 26g each to obtain 5 moles of silver (Ag).