2NaCl+2H2O >>2NaOH+H2+Cl2 if 1.9×10^6 (1900 metric tons) of Cl2 produced daily, estimate the quantities of H2 produced.
Here is a worked example of a stoichiometry problem. Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html
To estimate the quantity of H2 produced, we need to use the stoichiometry of the balanced chemical equation:
2NaCl + 2H2O → 2NaOH + H2 + Cl2
The ratio between Cl2 and H2 is 1:1, meaning for every one mole of Cl2 produced, one mole of H2 is also produced.
First, calculate the molar mass of Cl2. The molar mass of chlorine (Cl) is 35.45 g/mol, so the molar mass of Cl2 is 2 x 35.45 g/mol = 70.90 g/mol.
Next, convert the given amount of Cl2 to moles using the molar mass of Cl2:
1.9 × 10^6 metric tons = 1.9 × 10^6 × 1000 kg = 1.9 × 10^6 × 1000 × 1000 g
= 1.9 × 10^6 × 1000 × 1000 / 70.90 mol (moles)
Now, since the ratio of Cl2 to H2 is 1:1, the number of moles of H2 produced will be the same as the number of moles of Cl2. Therefore, the quantity of H2 produced in grams can be calculated as follows:
Mass of H2 = Number of moles of H2 × Molar mass of H2
= Number of moles of Cl2 × Molar mass of H2
= 1.9 × 10^6 × 1000 × 1000 / 70.90 × 2 g
After performing the calculations, the result will give you the estimated quantity of H2 produced in grams.