WHAT IS THE MASS IN GRAMS OF AMMONIA PRODUCED WHEN 280G NITROGEN REACTS TO FROM AMMONIA
Just follow the steps of this worked stoichiometry problem.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the mass of ammonia produced, you need to consider the balanced chemical equation for the reaction of nitrogen (N2) to ammonia (NH3). The balanced equation is:
N2 + 3H2 → 2NH3
This equation tells us that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
To calculate the mass of ammonia produced, we can follow these steps:
Step 1: Calculate the number of moles of nitrogen (N2) given the mass of nitrogen.
To find the number of moles, you need to divide the mass of nitrogen by its molar mass. The molar mass of nitrogen (N2) is 28 grams/mol.
Number of moles of N2 = Mass of N2 / Molar mass of N2
Number of moles of N2 = 280 g / 28 g/mol
Number of moles of N2 = 10 mol
Step 2: Use the balanced equation to determine the moles of ammonia (NH3) produced.
From the balanced equation, we know that 1 mole of nitrogen (N2) reacts to form 2 moles of ammonia (NH3). Therefore, if we have 10 moles of N2, we will have 20 moles of NH3.
Number of moles of NH3 = 2 × Number of moles of N2
Number of moles of NH3 = 2 × 10 mol
Number of moles of NH3 = 20 mol
Step 3: Calculate the mass of ammonia (NH3) using the number of moles and its molar mass.
The molar mass of ammonia (NH3) is the sum of the molar masses of one nitrogen atom (14 g/mol) and three hydrogen atoms (3 g/mol).
Molar mass of NH3 = 14 g/mol (molar mass of nitrogen) + 3 g/mol (molar mass of hydrogen)
Molar mass of NH3 = 17 g/mol
Mass of NH3 = Number of moles of NH3 × Molar mass of NH3
Mass of NH3 = 20 mol × 17 g/mol
Mass of NH3 = 340 g
Therefore, the mass of ammonia produced when 280 g of nitrogen reacts is 340 grams.