a two digit number has more ones than tens.what could the number be?how do you know your number is correct?how many number can you make?
is this whole answer
No. There are many more numbers that fit this description.
Read the problem again.
To find a two-digit number where the count of ones is greater than the count of tens, we can start by listing down all the possible two-digit numbers.
First, let's list the numbers from 10 to 99:
10, 11, 12, 13, ..., 97, 98, 99.
Now, for each number, we need to check if the count of ones is greater than the count of tens.
Let's go through the possible numbers one by one:
For the number 10, the count of ones is 1 and the count of tens is 1. Since both counts are equal, this number doesn't meet our condition.
For the number 11, the count of ones is 2 and the count of tens is 1. As the count of ones is greater than the count of tens, this number fulfills our condition.
For the number 12, the count of ones is 1 and the count of tens is 1. Since both counts are equal, this number doesn't meet our condition.
For the number 13, the count of ones is 1 and the count of tens is 1. Again, both counts are equal, so this number doesn't meet our condition.
We can continue this process for all the remaining numbers until we find all the numbers that satisfy the condition.
To check if our found number is correct, we can do a quick verification. Let's take the number 11, for example. The count of ones is 2, and the count of tens is 1. So, the number 11 does indeed have more ones than tens, and we can conclude it is correct.
Now, let's find all the numbers that fit the given condition:
From our analysis, we found one number, which is 11, that satisfies the condition.
Therefore, there is only one number that meets the given condition.
12, 35, 69
How many more numbers can you make?