statistics
posted by Janice .
If 86% of households have cable television and three households are picked at random, what is the probability that at least one of those three picked will have cable television?

Use a binomial probability table or use the formula to do this by hand:
P(0) = (nCx)(p^x)[q^(nx)]
n = 3
x = 0
p = .86
q = 1  p
Substitute the values into the formula and calculate P(0). Then subtract from 1 for your probability.