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If 86% of households have cable television and three households are picked at random, what is the probability that at least one of those three picked will have cable television?

  • statistics -

    Use a binomial probability table or use the formula to do this by hand:

    P(0) = (nCx)(p^x)[q^(n-x)]

    n = 3
    x = 0
    p = .86
    q = 1 - p

    Substitute the values into the formula and calculate P(0). Then subtract from 1 for your probability.

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