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a projectile is fired from the surface of the earth with a speed of 200 m/s at an angle of 30 degrees above the horizontal. If the ground is level, what is the maximum height reached by the projectile

  • physics -

    h = V^2(sin^2(30))/2g

  • physics -

    Vy= sin30(200)=100m/s

    t=(Vf-Vi)/a, t=(0-100)/9.81, t=10.3s

    Sy=Vy(t), Sy= 100(10.3), Sy= 1019m

  • physics -

    1019M

  • physics -

    509.7M

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