precalculus

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use remainder therem to find the remainder when f(x) is divided by x+2 then use factor to determine whether x +2 is a factor
f(x) = x^6 + 2x^5 + 3x^2 - 2x - 16

  • precalculus -

    f(-2) = (-2)^6 + 2(-2)^5 + 3(-2)^2 -2(-2) - 16
    = 64 -64 + 12 + 4 -16
    = 0

    so what do you think?

  • precalculus -

    It's actually what I got and it is a factor because it's zero right?

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