Write a molecular form of the equation for the reation CaCl2*2H2O/K2C2O4*H2O
It is very difficult without the medium.
Calcium acetate is very insoluble, however it is hygroscopic, in a non-aquesous envirnoment, it gains water to form Ca(C2O4).H20.
In a water solution, it probably has the forms CaC2O4.xH2O
potassium chloride in an aqueous solution is ions (aq).
So without more information on the reaction environment, this is about all you can get.
The reaction you mentioned involves the compounds CaCl2·2H2O (calcium chloride dihydrate) and K2C2O4·H2O (potassium oxalate monohydrate). Here is the molecular equation for the reaction:
CaCl2·2H2O + K2C2O4·H2O → CaC2O4 + 2KCl + 3H2O
In this reaction, calcium chloride dihydrate and potassium oxalate monohydrate react to form calcium oxalate (CaC2O4), potassium chloride (KCl), and water (H2O).
To write the molecular formula for the reaction between CaCl2·2H2O (calcium chloride dihydrate) and K2C2O4·H2O (potassium oxalate monohydrate), we need to indicate the products of the reaction.
First, let's break down the given compounds.
CaCl2·2H2O consists of calcium chloride (CaCl2) combined with two molecules of water (2H2O).
K2C2O4·H2O comprises potassium oxalate (K2C2O4) combined with one molecule of water (H2O).
Now, let's write the molecular form of the equation based on the combination of these compounds:
CaCl2·2H2O + K2C2O4·H2O ⟶ [products]
Since we haven't specified what the reaction products are, we can't provide a complete molecular equation.