Amy bought some stationary from a bookstore. The total cost of 3 files A,B,C was $5.60 more than the total cost of 4staples. A cost $1.90 less than each of the other 2files. B cost $4.20 more than each staple. Find the cost of C
$X = Cost of B.
$X = Cost of C.
X -!.90 = Cost of A.
X - 4.20 = Cost of each staple.
X + X + (X-1.90) = 4(X-4.20) + 5.60,
3x - 1.90 = 4x-16.80 + 5.60,
3x - 4x = -16.80 + 5.60 + 1.90 = -9.30,
-x = -9.30,
X = $9.30. = Cost of B.
X = $9.30 = Cost of C.
X-1.90 = 9.30 - 1.90 = $7.40=Cost of A.
To find the cost of file C, we can break down the given information and solve step by step.
Let's assume the cost of each staple is x dollars.
According to the given information:
1. The total cost of 3 files A, B, and C is $5.60 more than the total cost of 4 staples. This can be expressed as:
Cost of A + Cost of B + Cost of C = Cost of 4 staples + $5.60
2. A costs $1.90 less than each of the other two files. Let's assume the cost of A is y dollars. So, the cost of B is (y + $1.90) dollars, and the cost of C is (y + $1.90) dollars.
3. B costs $4.20 more than each staple. So, the cost of B is (x + $4.20) dollars.
Now, we can substitute these values into the first equation to solve for y:
(y) + (y + $1.90) + (y + $1.90) = 4x + $5.60
Simplifying the equation:
3y + $3.80 = 4x + $5.60
Rearranging terms:
3y = 4x + $5.60 - $3.80
3y = 4x + $1.80
Now, we have an equation connecting A (y) and staples (x).
To find the value of y and x that satisfy the equation, you would need additional information or values for the cost of the staples or the files.
Without additional information, we cannot determine the exact cost of file C.