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a car traveling initially at +7.0 m/s accelerates uniformly at the rate of +0.80m/s2 for a distance of 245 m. what is its velocity at the end of the acceleration?

  • physics -

    Just get out your good old

    v = at
    s = 1/2 at^2

    formulas and work with them a bit.

    We want to find out how long it will take to go 245m under acceleration.

    245 = 7t + .4t^2
    t = 17.5 sec

    v = 7 + .8*17.5 = 21.0 m/s

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