# Calculus

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use the intermediate value theorem to determine whether there is a zero
f(x) = -3^3 - 6x^2 + 10x + 9 ; [-1,0]

• Calculus -

f(-1) = -4
f(0) = 9

So, the IVT says that f(x) = 0 for x somewhere in [-1,0]

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