posted by Dawn .
"A line perpendicular to x + 3y = 5 passes through (1, -1). What is the
equation of the line in standard form?"
You have a point (1,-1) and a slope 3
The point-slope form is
y-(-1) = 3(x-1)
Rearrange terms to get to standard form:
y+1 = 3x-3
-3x + y = -4