Physics
posted by Sabrina .
An aircraft has a landing velocity of 50 ms1 and decelerates uniformly at 10 ms2Calculate:
(a) the time taken to reach 15 ms1
(b) the distance travelled during this time
(c) the velocity of the car when it was 100 m from the start point

a. t = (Vf  Vo) / a,
t = (15  50) / 10 = 3.5s.
b. d = Vo*t + 0.5a*t^2,
d = 50*3.5 + (5)(3.5)^2 = 113.75m.
c. Vf^2 = Vo^2 + 2a*d,
Vf^2 = (50)^2 + (20)100 = 500,
Vf = 22.36m/s.
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