A bike accelerates from 0.0m/s to 4.0m/s in 4s. what distance does it travel?
IS IT THO?
a = Vf - Vo) / t,
a = (4 - 0) / 4 = 1m/s^2.
d = Vo*t + 0.5a*t^2,
d = 0 + 0.5*4^2 = 8m.
nae nae befo you get a woopin
tf u thought
To find the distance traveled by the bike, we can use the formula:
distance = initial velocity × time + 0.5 × acceleration × time^2
Given:
Initial velocity (u) = 0.0 m/s
Final velocity (v) = 4.0 m/s
Time (t) = 4.0 s
First, let's calculate the acceleration (a) using the formula:
acceleration = (final velocity - initial velocity) / time
acceleration = (4.0 m/s - 0.0 m/s) / 4.0 s
acceleration = 4.0 m/s / 4.0 s
acceleration = 1.0 m/s²
Now that we have the acceleration, we can substitute the values into the distance formula:
distance = 0.0 m/s × 4.0 s + 0.5 × 1.0 m/s² × (4.0 s)^2
Simplifying the formula:
distance = 0 + 0.5 × 1.0 m/s² × 16.0 s²
distance = 0.5 m/s² × 16.0 s²
distance = 8.0 m
Therefore, the bike travels a distance of 8.0 meters.