i am a 4-digit whole number. my digits decrease by 2 from the thousands place to the ones place. each of my digits is an even number. what number am I?
8,642
8,642
8642
To find the number that meets the given criteria, we can use the following steps:
Step 1: Start with the thousands digit.
Since the digits decrease by 2 from the thousands place to the ones place, the thousands digit must be the highest even number possible. The highest even digit is 8, so the thousands digit is 8.
Step 2: Move to the hundreds digit.
Since the digits decrease by 2, the hundreds digit is 2 less than the thousands digit. Therefore, the hundreds digit is 8 - 2 = 6.
Step 3: Proceed to the tens digit.
Again, since the digits decrease by 2, the tens digit is 2 less than the hundreds digit. Therefore, the tens digit is 6 - 2 = 4.
Step 4: Finally, determine the ones digit.
Following the pattern, the ones digit is 2 less than the tens digit. Therefore, the ones digit is 4 - 2 = 2.
Putting it all together, the number that meets the given criteria is 8642.