In an 8.00 race, one runner runs at a steady 11.8 and another runs at 14.5 .How far from the finish line is the slower runner when the faster runner finishes the race?

Can't work without units.

A toy train is pushed forward and released at = 3.5 m with a speed of 1.0m/s . It rolls at a steady speed for 1.2s , then one wheel begins to stick. The train comes to a stop 3.4m from the point at which it was released.What is the train's acceleration after its wheel begins to stick?

and the other question is

km/h the units i mean
so the question is
in an 8.00km race, one runner runs at a steady 11.8km/h and another runs at 14.5km/h .How far from the finish line is the slower runner when the faster runner finishes the race?

relative distance= relative velocity*time

= (14.5-11.8)km/hr * time

but time= 8km/14.5(km/hr)= 8/14.5 hr

relative distance= (above)*8/14.5 km

im sorry bob but i don't get it :(

i don't understand what you mean

To find out how far the slower runner is from the finish line when the faster runner finishes the race, we need to calculate the time it takes for the faster runner to finish the race and then use that time to determine how far the slower runner has run.

First, let's calculate the time it takes for the faster runner to finish the race. We can use the formula:

time = distance/speed

For the faster runner, the distance is 8.00 miles and the speed is 11.8 miles per hour. Substituting these values into the formula:

time = 8.00 miles / 11.8 miles per hour
time = 0.6779661017 hours

Now, we can use this time to determine how far the slower runner has run. The slower runner runs at a speed of 14.5 miles per hour, so:

distance = speed * time
distance = 14.5 miles per hour * 0.6779661017 hours
distance = 9.8428312945 miles

Therefore, the slower runner is approximately 9.84 miles from the finish line when the faster runner finishes the race.