What are the products for the reaction of Sodium hydrogen phosphate with nickel II nitrate
Ni2HPO4 + Ni(NO3)2 -->
To determine the products of the reaction between sodium hydrogen phosphate (Na2HPO4) and nickel II nitrate (Ni(NO3)2), we need to apply the principles of chemical formula writing and balancing.
First, let's identify the ions present in the reactants:
- Sodium hydrogen phosphate (Na2HPO4) dissociates into three ions: 2 Na+ ions, 1 HPO4^2- ion
- Nickel II nitrate (Ni(NO3)2) dissociates into three ions: 1 Ni^2+ ion, 2 NO3- ions
Now, let's exchange the ions to form the products:
- The Ni^2+ ion will combine with the HPO4^2- ion to form nickel(II) phosphate, which has the chemical formula Ni3(PO4)2.
- The two Na+ ions from sodium hydrogen phosphate and the two NO3- ions from nickel II nitrate do not participate in any further reaction and remain as spectator ions.
Therefore, the products of the reaction are nickel(II) phosphate (Ni3(PO4)2), two Na+ ions, and two NO3- ions. The balanced equation for the reaction is:
3Ni2HPO4 + 2Ni(NO3)2 -> 2Ni3(PO4)2 + 2NaNO3.