What is the concentration of a standard solution? - It was prepare to 250mL, it contained 9.7563g (O.lM) of (NH4) and 3mL of sulphuric acid.
To determine the concentration of the standard solution, we need to calculate the moles of solute and divide by the volume of the solution.
First, let's calculate the moles of (NH4)2SO4 in the solution:
1. Determine the molar mass of (NH4)2SO4:
- Molar mass of NH4 = 14.007 g/mol
- Molar mass of S = 32.06 g/mol
- Molar mass of O4 = 4 x 16.00 g/mol = 64.00 g/mol
- Molar mass of (NH4)2SO4 = 2 x (Molar mass of NH4) + Molar mass of S + 4 x (Molar mass of O) = 2 x 14.007 g/mol + 32.06 g/mol + 4 x 16.00 g/mol = 132.14 g/mol
2. Calculate the moles of (NH4)2SO4 using the given mass:
- Moles = mass / molar mass = 9.7563 g / 132.14 g/mol
Next, let's determine the volume of the solution:
- The solution was prepared in a 250 mL volume.
Finally, calculate the concentration (in mol/L or M) of the solution:
- Concentration (M) = moles / volume (L)
- Convert the volume from mL to L (divide by 1000): 250 mL / 1000 mL/L = 0.25 L
- Concentration (M) = (moles of (NH4)2SO4) / (volume of solution in liters)
So, to find the concentration, divide the moles of (NH4)2SO4 by the volume in liters (0.25 L).
Additionally, it's worth noting that the addition of sulfuric acid (H2SO4) doesn't impact the concentration of the (NH4)2SO4 standard solution since it doesn't react with (NH4)2SO4.