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A home run is hit such a way that the baseball just clears a wall 30 m high located 117 m from home plate. The ball is hit at an angle of 40 degrees to the horizontal, and air resistance is negligible. Assume the ball is hit at a height of 2 m above the ground. The acceleration of gravity is 9.8 m/s^2.

What is the initial speed of the ball?
Answer in units of m/s

  • Physics -

    You need to solve two simultaneous equations for the time of flight (T) and initial velocity, Vo.

    Vo cos40 T = 117 meters
    Vo*T = 152.7 m,


    2 + Vo sin40 T- (g/2) T^2 = 30 meters
    0.6428 Vo*T - 4.9 T^2 = 28

    Solve for T first, then Vo

    98.17 -4.9 T^2 = 28
    T = 3.99 s


  • Physics -


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