posted by miley .
Need help asap! what is the limit as x approaches 0 of -x/tan(3x) ?
You should have either proved or collected several basic trig limits
limit sinx/x as x---> 0 = 1
lim tanØ/Ø as Ø ---> 0 = 1 which implies lim Ø/tanØ as Ø ---> 0 = 1
so let's make your question look like that
= lim -3x/(3tan(3x))
= lim (-1/3) [(3x)/tan(3x)] , (where 3x = Ø)
= lim (-1/3) [Ø/tanØ]