I am a bit confused on working this problem:
Given that the work function (ƒÖ) for a metal is 1.82 eV, calculate the threshold frequency for
this metal.
http://en.wikipedia.org/wiki/Work_function
To calculate the threshold frequency for a metal, we need to use the relationship between energy and frequency. Specifically, we can use the formula:
E = h × f
Where:
- E is the energy (in Joules)
- h is the Planck's constant (6.626 × 10^-34 J·s)
- f is the frequency (in Hz)
In this case, we need to convert the work function from electron volts (eV) to Joules. To do this, we can use the conversion factor:
1 eV = 1.602 × 10^-19 J
Given that the work function (ƒÖ) for the metal is 1.82 eV, we can convert it to Joules:
1.82 eV × (1.602 × 10^-19 J/eV) = 2.920 × 10^-19 J
Now, we can rearrange the formula E = h × f to solve for the frequency:
f = E / h
Plugging in the values:
f = (2.920 × 10^-19 J) / (6.626 × 10^-34 J·s)
Now, let's calculate the threshold frequency.