sketch the graph of the line defined by y 2 +4 using the dual-intercept method.
Do you mean y = x^2 + 4?
There is a y-axis intercept when x = 0, at (0, 4)
There is no x-axis intercept where y = 0, since x^2 would have to be negative.
This equation is best plotted with a few other points. We don't draw graphs here.