calculus
posted by Shayne .
Find an equation of the normal line to the parabola
y = x2 − 7x + 5
that is parallel to the line
x − 3y = 3.

dy/dx = 2x7 which is the slope of the tangent.
so the normal must have a slope of 1/(2x7) or 1/(72x)
but that is supposed to be parallel to x3y=3
that is, a slope of 1/3
1/(72x) = 1/3
3 = 72x
2x = 4
x = 2
when x=2, y = 414+5 = 5
so the normal has equation
x  3y = c
with (2,5) on it, so
2 + 15 = c
equation of normal is
x  3y = 15
check: at (2,5) slope should be 3
dy/dx = 2(2)7 = 3
My answer for the equation of the normal is correct!!