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posted by dan Wednesday, September 14, 2011 at 8:27pm.

a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?

x = Vi t + (1/2) a t^2 125 = (25000/3600)(12) + .5 * a * 144 solve for a then v = Vi + a t

where did you get the 144

ok i get

correct me if im wrong solve for a = 102 and v = 1249

A = 51.15 V= 638.8

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