calories given off when 89g of water cools from 44degrees C to 29 degrees C
q = mass water x specific heat water x (Tfinal-Tinitial).
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To calculate the calories given off when water cools, you need to use the specific heat capacity of water and the formula:
Q = mcΔT
Where:
Q is the energy transferred (calories)
m is the mass of the substance (in grams)
c is the specific heat capacity (calories per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
Step 1: Find the specific heat capacity of water:
The specific heat capacity of water is approximately 1 calorie per gram per degree Celsius (1 cal/g°C).
Step 2: Plug the values into the formula:
m = 89g (given)
c = 1 cal/g°C (specific heat capacity of water)
ΔT = (29°C - 44°C) = -15°C (since it's cooling, the change in temperature will be negative)
Q = (89g) x (1 cal/g°C) x (-15°C)
Step 3: Calculate the energy transferred:
Q = (-1,335 cal)
Therefore, the water gives off 1,335 calories (cal) when cooling from 44°C to 29°C.