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A tennis ball with a speed of 25.9 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 21.3157 m/s.
If the ball is in contact with the wall for
0.0133 s, what is the average acceleration of
the ball while it is in contact with the wall?

  • uta -

    We do not recognize uta as a School Subject. Look to the upper left for a choice.


  • physics -

    Divide the velocity change by the time interval. Note that the bounceback velocity is negative.

    Acceleration = [25.9 -(-21.3157)]/0.0133
    = 3550 m/s^2

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