INSERT THE SEVEN ARITHMETIC MEANS BETWEEN 3 AND 9
Which arithmetic means?
THE QUESTION JUST SAYS INSERT SEVEN ARITHMETIC MEANS BETWEEN 3 AND 9
You need a set of data to have an arithmetic mean.
http://www.mathgoodies.com/lessons/vol8/mean.html
THIS IS FOR ALGEBRA/PRE-CALCULUS MATH. I POSTED IT JUST AS THE TEACHER WROTE IT.
terms:
3, 3+d, 3+2d, 3+3d, 3+ 4d, 3+5d, 3+6d, 3+7d , 9
so we now have 9 terms
a = 3,
term(9) = a+8d = 9
3 + 8d = 9
d = 6/8 = 3/4 or .75
the 7 terms are:
3.75, 4.5, 5.25, 6, 6.75, 7.5, 8.25
Or you could go on the long way method
Supposedly the question doesn't only have numbers e.g (3p-q) and (-13p+7q)
Where (3p-q) is the first term and (-13p+7q) is the ninth term.
You take the 1st term add it with the last and divide the sum by 2
But remember that it will give you the 5th term
Then take the sum of the 5th and the 1st to get the 3rd term.
You do that until you get the rest.
Now let's look at your question [(3+9)/2]= 6 right? That's the 5th term
[(3+6)/2]=4.5 which is the 3rd term
So you go on to find the rest.
Good luck :-)
To insert the seven arithmetic means between 3 and 9, we need to find the common difference between each term.
First, find the difference between the two given terms:
9 - 3 = 6
Then, divide this difference by the number of terms you want to insert plus 1 (since there will be eight terms in total):
6 / 8 = 0.75
Now, we can calculate each arithmetic mean by adding 0.75 to the previous term.
Starting with 3, we add 0.75 successively to find the eight terms:
Term 1: 3
Term 2: 3 + 0.75 = 3.75
Term 3: 3.75 + 0.75 = 4.5
Term 4: 4.5 + 0.75 = 5.25
Term 5: 5.25 + 0.75 = 6
Term 6: 6 + 0.75 = 6.75
Term 7: 6.75 + 0.75 = 7.5
Term 8: 7.5 + 0.75 = 8.25
So, the seven arithmetic means between 3 and 9 are:
3.75, 4.5, 5.25, 6, 6.75, 7.5, and 8.25.