An automobile with an initial speed of 4.82 m/s accelerates uniformly at the rate of 2.2 m/s2. Find the displacement of the car after 5.9 s. Answer in units of m
To find the displacement of the car, we can use the equation of motion:
displacement (s) = initial velocity (u) * time (t) + (1/2) * acceleration (a) * time squared (t^2)
Given:
Initial velocity (u) = 4.82 m/s
Acceleration (a) = 2.2 m/s^2
Time (t) = 5.9 s
Using the equation, we can substitute the given values:
s = (4.82 m/s) * (5.9 s) + (1/2) * (2.2 m/s^2) * (5.9 s)^2
s = 28.438 m + (1/2) * 2.2 m/s^2 * 34.81 s^2
s = 28.438 m + (0.5) * 2.2 m/s^2 * 34.81 s^2
s = 28.438 m + 1.1 m/s^2 * 34.81 s^2
s = 28.438 m + 38.291 m
s = 66.729 m
Therefore, the displacement of the car after 5.9 s is 66.729 m.
d= Vi*t+ 1/2 a t^2
memorize this formula.