Consider the series defined by Sn = 3n-1
Find the first four terms of the series.
How exactly do I do this?
S1= 3*1 -1 = 2
S2 = 3*2 -1 = 5
S3 = 3*3 -1 = 8
etc.
keep increasing N
Well, if you want to find the first four terms of the series defined by Sn = 3n-1, you can just plug in the values of n and do a little bit of math. Let's take it step by step:
1) When n = 1, plug it into the equation:
S1 = 3(1) - 1 = 2
2) When n = 2:
S2 = 3(2) - 1 = 5
3) When n = 3:
S3 = 3(3) - 1 = 8
4) When n = 4:
S4 = 3(4) - 1 = 11
So, the first four terms of the series are 2, 5, 8, and 11. Voila!
To find the first four terms of the series defined by Sn = 3n - 1, you simply need to substitute the values of n from 1 to 4 into the equation and calculate the corresponding values of Sn.
Let's calculate the first four terms step by step:
1. Substitute n = 1:
S1 = 3(1) - 1 = 2
2. Substitute n = 2:
S2 = 3(2) - 1 = 5
3. Substitute n = 3:
S3 = 3(3) - 1 = 8
4. Substitute n = 4:
S4 = 3(4) - 1 = 11
Therefore, the first four terms of the series are 2, 5, 8, and 11.
To find the first four terms of the series defined by Sn = 3n - 1, you need to substitute the values of n from 1 to 4 into the equation and calculate the corresponding values of Sn.
Here's how you can do it step by step:
1. Start with n = 1.
Substitute n = 1 into the equation Sn = 3n - 1:
S1 = 3(1) - 1 = 3 - 1 = 2
So, the first term of the series is 2.
2. Move on to n = 2.
Substitute n = 2 into the equation Sn = 3n - 1:
S2 = 3(2) - 1 = 6 - 1 = 5
The second term of the series is 5.
3. Continue with n = 3.
Substitute n = 3 into the equation Sn = 3n - 1:
S3 = 3(3) - 1 = 9 - 1 = 8
The third term of the series is 8.
4. Lastly, consider n = 4.
Substitute n = 4 into the equation Sn = 3n - 1:
S4 = 3(4) - 1 = 12 - 1 = 11
The fourth term of the series is 11.
Therefore, the first four terms of the given series are 2, 5, 8, and 11.