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2y+6,3y and y-4 are all integers and y-4 is the median of these intergers which of the following could not be value of y?

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    2y+6,3y and y-4 are all integers and y-4 is the median of these intergers
    =>
    case 1:
    2y+6≥y-4 AND 3y≤y-4
    2y+6≥y-4 => y≥-10
    AND
    3y≤y-4 => y≤-2
    =>
    -10≤y≤-2

    or case 2:
    2y+6≤y-4 AND 3y≥y-4
    solving similarly,
    -2≤y≤-10
    which is impossible.

    Now you only have to figure out the invalid choice from your list.

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