physics

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a ball is dropped from height 10 m. it rebounds to a height of 5m.the ball was in contact with the floor for 0.01s what was its acceleration during contact?

  • physics -

    u = root ( 2gh)
    u = root(2 * 9.8 * 10)
    u = root(196
    u = 14 m / s
    v = root(2gh)
    v = root(2*9.8 * 5)
    v = root(98)
    v = root 98
    v = 7 root2

    14 + 7 root2

    Acceleration = (14+7root2)/ 0.01
    = 7(2 + root2) / 0.01
    = 700(2 + root2)
    700(2 + 1.4142)
    = 700(3.4142)
    = 341.42 *7
    = 2389.94 m/sec^2

  • physics -

    hnfnn
    b
    c
    bc
    bf
    59m/s^2

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