The magnitude of A=(-4m)x+(-2m)y=
are you using x,y to mean unit vectors that are 90 degrees apart? If so
mag(a)=sqrt(-4m)^2 + (-2m)^2
=sqrt (20m^2) and you can finish it.
how do i finish it?
If you do not know how to get the square root of (20*m^2), you will need a tutor immediately.
sqrt(20m^2)=m*sqrt(4*5)=2m*sqrt(5)
Good luck with physics. I strongly recommend a tutor before you are lost.
To find the magnitude of vector A, we can use the formula:
|A| = sqrt(Ax^2 + Ay^2)
Where Ax and Ay are the components of vector A in the x and y directions respectively.
Given that A = (-4m)x + (-2m)y, we can plug in these values into the formula:
|A| = sqrt((-4m)^2 + (-2m)^2)
Simplifying:
|A| = sqrt(16m^2 + 4m^2)
|A| = sqrt(20m^2)
Taking the square root of 20m^2 gives us:
|A| = 2m * sqrt(5)
Therefore, the magnitude of vector A is 2m times the square root of 5.