posted by Raymond .
How would you solve for X if X was the hypotenuse of a 45-45-90 triangle and the other two sides were Square Root of 11?
Use Pythagoras theorem:
hypotenuse² = side1²+side2²l
= 11 + 11
hypotenuse = √22
Thank you very much! I thought it was 2 Square Roots of 11. You saved me.
The method I have shown above is more general, and applies to any right-triangle.
For a 45-45-90 triangle, you were close with the answer. A short-cut would be to multiply each side by √2, which makes:
√2 * √11